1788–89 United States presidential election in New Hampshire
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The 1788–89 United States presidential election in New Hampshire took place on January 7, 1789, as part of the 1788–89 United States presidential election to elect the first President. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.
New Hampshire unanimously voted for independent candidate and commander-in-chief of the Continental Army, George Washington. The total vote was composed of 1,759 for Federalist electors, all of whom were supportive of Washington.[1] Several candidates of unknown affiliation also received votes.
No elector candidate received the majority of votes, throwing the election to the legislature, who chose the five best-performing elector candidates.[1]
Results
1788-1789 United States presidential election in New Hampshire | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
Independent | George Washington | 1,759 | 100.00% | 5 | |
Totals | 1,759 | 100.00% | 5 |
See also
References
- ^ a b "A New Nation Votes". elections.lib.tufts.edu. Retrieved July 16, 2024.
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